What is the value of Negative 3 squared + (negative 4 + 7) (2)? –28 –3 3 15

Mathematics

2 answers:

Marina CMI [18]3 years ago

5 0

Answer:

Step-by-step explanation:

$( - 3)^{2} + ( - 4 + 7)(2) \\ = 9 + 3 \times 2 \\ = 9 + 6 \\ = 15$

Sunny_sXe [5.5K]3 years ago

3 0

<h2>Ans<u><em>wer:</em></u></h2><h2><u><em> Since the rate of change with each value is 12, 12x will appear somewhere in the formula for this sequence. = 12x + c, where c is a constant value. The tenth term gives a value of 52. So, 52 = 12(10) + </em></u>c c = -68 </h2>

Step-by-step explanation:

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Solve for x. 3x−1=9x+2 Enter your answer in the box. x =

julia-pushkina [17]

Answer:

x= -1

Step-by-step explanation:

3x-1=2x2 (calculate the product)

3x-1=4x (move terms)

3 x - 4 x =1 (collect the terms)

- x = 1 (change the signs)

Solution is x = -1

3 0

3 years ago

Read 2 more answers

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$