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Aleksandr [31]
3 years ago
8

6(x+4)= how to solve this ?

Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer: 6x + 24

Explanation: In this problem, the 6 "distributes" through the parenthses, which means that it multiplies by each of the terms inside.

So we have 6(x) + 6(4) which simplifies to 6x + 24.

tiny-mole [99]3 years ago
4 0
Distribute
6x + 24 = 0

subtract 24 from both sides
6x = -24

divide both sides by 6 to isolate x
x = -4
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Answer:

Option C. 154 cm²

Step-by-step explanation:

From the question given above, the following data were obtained:

Pi (π) = 22/7

Diameter (d) = 14 cm

Area (A) =?

Next, we shall determine the radius of the circle. This can be obtained as follow:

Diameter (d) = 14 cm

Radius (r) =?

r = d/2

r = 14/2

r = 7 cm

Finally, we shall determine the area of the circle as illustrated below:

Pi (π) = 22/7

Radius (r) = 7 cm

Area (A) =?

The area of a circle can be obtained by using the following formula:

A = πr²

A = 22/7 × 7²

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nikklg [1K]

A. 2

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The width of a rectangle is only 15% of its length. If the perimeter of the rectangle is 46, what is the length
sveta [45]

Answer:

20 units

Step-by-step explanation:

Let the length be x. According to the question,

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  • Width = 15% of the length

➝ Width = 15% of the length

➝ Width = 15/100x

➝ Width = 3/20x

We have the perimeter of the rectangle that is 46 units.

\longrightarrow \sf {Perimeter_{(Rec.)} = 2(L + W) } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{20x + 3x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{23x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {\dfrac{46}{2}=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23 \times 20 = 23x} \\

\longrightarrow \sf {460= 23x} \\

\longrightarrow \sf {\cancel{\dfrac{460}{23}} = x} \\

\longrightarrow \underline{\boxed{ \bf {20\; units = x}}} \\

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Answer:

  see the attached diagram

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