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slamgirl [31]
3 years ago
14

Write a number with two decimal places, that is bigger than 4 wholes and 1/5 but smaller than 4.25

Mathematics
1 answer:
OleMash [197]3 years ago
6 0

Answer :

11.45

step-by-step explantion :

4.25=17/4

when we add 41/5 and 17/4, we get

41×4+17×5/4×5

164+65/20

229/20

11.45 Ans

:

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Michael needs to lease out a Inusic studio to record his new album. The studio charges an intial studio- use fee of $300 plus an
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$300 + $200x

Step-by-step explanation:

So to even use the studio you need to pay $300. For every hour you use the studio you have to pay $200 dollars. So the price would end up as $300 + $200x. The variable stands for how many hours Michael uses the studio.

3 0
2 years ago
K/75 + 57.1 = 40.8<br> k = ?
Ronch [10]
K/75 + 57.1 = 40.8

k/75 = 40.8 - 57.1

k/75 = -16.3

k = -16.3 • 75

k = -1222.5 or -1222 1/2

Hope it helps!
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3 years ago
Sally is selling handmade bracelets to raise money for breast cancer awareness.She created the given equation to represent her p
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3 years ago
When the temperature in London is 5 degrees celsius, the temperature in New York is - 7 degrees C. If the temperature in London
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6 0
2 years ago
a right angled triangle has sides which are 2cm and 7cm shorter than its hypotenuse find the length of the hypoenuse
vekshin1

Answer:

The length of the hypotenuse side is (9 + 2·√7) cm

Step-by-step explanation:

The given parameters of the triangle are;

The type f triangle = Right triangle

The length of the sides 2 cm and 7 cm shorter than the hypotenuse

Let 'h' represent the length of the hypotenuse side of the triangle, in centimeters we have;

The length of one side of the right triangle = (h - 2) cm

The length of the other side of the right triangle = (h - 7) cm

By Pythagoras's theorem, we have;

h² = (h - 2)² + (h - 7)²

Using search function on the internet, we have;

h² = (h - 2)² + (h - 7)² = 2·h² - 18·h + 53

∴ h² = 2·h² - 18·h + 53

∴ 2·h² - 18·h + 53 = h²

h² - 18·h + 53 = 0

53 is a prime number, therefore, by the quadratic formula, we have;

h = (18 ± √((-18)² - 4×1×53))/(2 × 1)

h = 9 + 2·√7 cm ≈ 14.29 cm or h = 9 - 2·√7 ≈ 3.71

However, given that one of the side is 7 cm shorter than the hypotenuse, for all the sides to remain positive, we have h = 9 + 2·√7 cm ≈ 14.29 cm , because for h ≈ 3.71 cm, we have;

The length of the other side = (h - 7) cm ≈ (3.71 - 7) cm ≈ -3.29 cm which is not possible for a real triangle

Therefore, the length of the hypotenuse side, h = 9 + 2·√7 cm ≈ 14.29 cm.

5 0
2 years ago
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