The factors of 20 are 1, 2, 4, 5, 10, 20
The factors of 30 are 1, 2, 3, 5, 6, 10, 15, 30
The factors of 45 are 1, 3, 5, 9, 15, 45
Hence the common factors are only 1 and 5.
The highest common factors in this case is only 5.
Hope this helps : )
X^4+ 3x^3+4x^2-8 | x+2 = x^3+x^2+2x-4
-x^4-2x^3
-----------------------
x^3+4x^2-8
-x^3-2x^2
-------------------------
2x^2-8
-2x^2-4x
--------------
-4x-8
4x+8
----------------------------
/ /
is a factor because (x+2)(x^3+x^2+2x-4)=x^4+3x^3+4x^2-8
Ax^2 + bx + c
a = 1
b = -4
c = -5
x^2 -4x-5
-5x1 = -5
-5+1 = -4
(factors of c that also add up to b)
ANSWER: (x-5) (x+1)
I believe the answer is 279.98.
9514 1404 393
Answer:
11 cm by 33 cm
Step-by-step explanation:
You can solve this problem mentally as follows.
Consider the rectangle as 3 squares, side-by-side. Then the area of each of those squares is 363/3 = 121 cm^2. From your knowledge of the squares of numbers, you know that 121 = 11^2. So, the width of the rectangle is 11 cm, and the length is 3 times that, or 33 cm.
_____
Using variables, we can let w represent the width. Then 3w can represent the length, and the area is ...
A = LW
A = (3w)(w) = 3x^2 = 363
w^2 = 363/3 = 121
w = √121 = 11
3w = 3·11 = 33
The width is 11 cm; the length is 33 cm.
