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zmey [24]
3 years ago
8

Given the number of hours spent amusing ourselves to death with screen time, how many Titanics could we have built in one year i

f all those hours had been spent building Titanics
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0

Answer:

12

Step-by-step explanation:

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Help Please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Kamila [148]

Answer:

x = 80°

Step-by-step explanation:

Angle on a straight line = 180°

(x + 40)° + (x - 20)° = 180°

x + 40° + x - 20° = 180°

2x + 20° = 180°

2x = 180° - 20°

2x = 160°

x = 160°/2

x = 80°

Check:

(x + 40)° + (x - 20)° = 180°

(80° + 40°) + (80° - 20°) = 180°

120° + 60° = 180°

180° = 180°

3 0
2 years ago
Sharon manages the Spirit Supply store at Lakefield Middle School. She tracks the sale of various items in her inventory so that
Airida [17]
Here is a graph. I hope it helped :)

7 0
3 years ago
Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.
fenix001 [56]

Answer:

The angle between vector \vec{u} = 5\, \vec{i} - 8\, \vec{j} and \vec{v} = 5\, \vec{i} + \, \vec{j} is approximately 1.21 radians, which is equivalent to approximately 69.3^\circ.

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

  • their dot products, and
  • the product of their lengths.

To be precise, if \theta denotes the angle between \vec{u} and \vec{v} (assume that 0^\circ \le \theta < 180^\circ or equivalently 0 \le \theta < \pi,) then:

\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}.

<h3>Dot product of the two vectors</h3>

The first component of \vec{u} is 5 and the first component of \vec{v} is also

The second component of \vec{u} is (-8) while the second component of \vec{v} is 1. The product of these two second components is (-8) \times 1= (-8).

The dot product of \vec{u} and \vec{v} will thus be:

\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}.

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both \vec{u} and \vec{v}:

  • \| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}.
  • \| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}.

<h3>Angle between the two vectors</h3>

Let \theta represent the angle between \vec{u} and \vec{v}. Apply the formula\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} to find the cosine of this angle:

\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}.

Since \theta is the angle between two vectors, its value should be between 0\; \rm radians and \pi \; \rm radians (0^\circ and 180^\circ.) That is: 0 \le \theta < \pi and 0^\circ \le \theta < 180^\circ. Apply the arccosine function (the inverse of the cosine function) to find the value of \theta:

\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ .

3 0
3 years ago
i just missed a couple says of school and i need someone to explain how to do this to me: please help
algol [13]
Remember the formula y = mx+b.

'm' in mx is the slope.

'b' is the y-intercept.

So in the equation y = -3x - 3...

The slope is -3. The y-intercept is -3.

I hope you find this answer the most helpful! :)
3 0
3 years ago
Which shows another way to write 73?
nata0808 [166]
None of the above, 3<span>× 3 × 3 × 3 × 3 × 3 × 3= 2187, 7 x 3= 21, 7x7x7= 343, and 7+7+7 is 21.</span>
8 0
3 years ago
Read 2 more answers
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