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3 years ago

Please answer seriously no playing around

Mathematics

2 answers:

Bingel [31]3 years ago

8 0

PeRIMeter is the RIM around the figure.
P= 5+5+12+12= 34 cm
Area is the dimension of surface inside
A= 5• 12= 60 cm^2

Previous dimensions in feet are
1 cm = 3 feet
12 cm = 3•12= 36 feet
5 cm= 3•5= 15 feet
If you add 2 foot around the pool New dimensions will be
36+2 to the left+2 to the right = 40 feet
15+4= 19 feet
Perimeter = 40•2+19•2= 80+ 38= 118 feet

Zolol [24]3 years ago

5 0

Perimeter : 34
Area : 60
If u want explanation Tell me ! :D

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3 years ago

Alaina has 7 in her bank account and earns 6 each day . joel has 48 in his banck account and earn 8 earch day in how many days w

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I think you wrote something wrong.

Step-by-step explanation:

If Alaina has $7 in her bank account and Joel had $48 in his Joel already has more then Alaina but I will attempt to teach you how to solve these types of problems.

for this example I'm giving Alaina 79 dollars.

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3 years ago

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Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

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