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iragen [17]
2 years ago
8

Calculate the percent yield if 500 grams of C7H8 makes 255 grams of C7H7NO2

Mathematics
2 answers:
eimsori [14]2 years ago
7 0
I’m still thinking about it
lakkis [162]2 years ago
3 0
500/92 = 5.43 mol of C7H8
1:1 mol ratio
Mass = mol x Mr = 5.43 x 137 = 743 g (theoretical yield)
Percentage yield = ( actual yield / theoretical yield ) x 100
500/743 x 100 = 67.3% 1dp
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Answer:

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Step-by-step explanation:

<em><u>By </u></em><em><u>Question</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>

  • Sum of numbers = 90 .
  • Difference of numbers = 18 .

<em><u>Let </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>

  • First Number be x .
  • Second number be y .

<em><u>According</u></em><em><u> to</u></em><em><u> </u></em><em><u>1</u></em><em><u>s</u></em><em><u>t</u></em><em><u> </u></em><em><u>condition</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>

: \implies x + y = 90

<u>According</u><u> to</u><u> </u><u>2</u><u>n</u><u>d</u><u> </u><u>condition</u><u> </u><u>:</u><u>-</u><u> </u>

: \implies x - y = 18

<em><u>Adding</u></em><em><u> the</u></em><em><u> </u></em><em><u>equations</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>

: \implies 2x = 18 + 90

: \implies 2x = 108

: \implies x = 54

<em><u>Therefore</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>

: \implies First number = 54

: \implies Second number = 36

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