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4 years ago

What is the approximate volume of the cylinder Use 3.14 for it

Mathematics

2 answers:

puteri [66]4 years ago

5 0

Answer:

904.32

Step-by-step explanation:iready

ryzh [129]4 years ago

4 0

Answer:

The volume of the cylinder is 904.32cm³

Step-by-step explanation:

To calculate the volume of a cylinder we have to use the following formula:

v = volume

h = height = 8cm

π = 3.14

r = radius = 6cm

v = (π * r²) * h

we replace with the known values

v = (3.14 * (6cm)²) * 8cm

v = (3.14 * 36cm²) * 8cm

v = 113.04² * 8cm

v = 904.32cm³

The volume of the cylinder is 904.32cm³

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I NEED HELP ASAPPPP

Yuliya22 [10]

Pythagorean Theorem- A^2+B^2=C^2
1) 6^2+9^2= x^2
2) 36+81= 117
Square root 117 =10.82

Hope this helped :)

4 0

3 years ago

Find the area of the shaded regions. Give your answer as a completely simplified

Pavel [41]

The area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

We have a circle in which the shaded region is shown.

The radius of the small circle r = 3 cm

The radius of the large circle R = 3+4 = 7 cm

The area of the shaded region:

= area of the large circle sector - an area of the small circle sector

= (120/360)[π7²] - (120/360)[π3²]

= 49π/3 - 3π

= 40π/3 square cm or

= 13.34π square cm

Thus, the area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.

Learn more about circle here:

brainly.com/question/11833983

#SPJ1

5 0

2 years ago

Can someone please explain how to do this!!!

DedPeter [7]

Hi there!

So we are given that:-

tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

Using the Identity

$\large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}$

Substitute tan theta = 7/24 in.

$\large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }$

Evaluate.

$\large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}$

Reminder -:

$\large \displaystyle{ sec \theta = \frac{1}{cos \theta} }$

Hence,

$\large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}$

Because in QIII, cos<0. Hence,

$\large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}$

Using the Pythagorean Theorem

$\large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }$

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

$\large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}$