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2 years ago

13

A computer is sold with or without a monitor, with or without a keyboard, with or without a DVD player, and with or without a Zi

p drive. How many different choices are there?

1 answer:

balandron [24]2 years ago

7 0

None because the computer need all parts to function

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Emma is ready to open a new checking account and is trying to decide between three banks using the chart below:

soldier1979 [14.2K]

where is the chart

Step-by-step explanation:

6 0

3 years ago

Work out the shaded area of this shape.

aliina [53]

Answer:

73

Step-by-step explanation:

5 0

3 years ago

Devon made a box with length x+1, width x+3, and height x-3. What is the volume of Devon's box as a function of x?

erica [24]

Answer:

(a)

$V=x^3+x^2-9x-9$

(b)

$x=10$

(c)

$x=\frac{7}{2}$

Step-by-step explanation:

we are given

length is x+1

$L=x+1$

width is x+3

$W=x+3$

height is x-3

$H=x-3$

(a)

we can use volume formula

$V=L\times W\times H$

now, we can plug it

$V=(x+1)\times (x+3)\times (x-3)$

now, we can simplify it

$V=x^3+x^2-9x-9$

(b)

we are given volume =1001

so, we can set V=1001

and then we can solve for x

$V=x^3+x^2-9x-9=1001$

now, we can factor it

$\left(x-10\right)\left(x^2+11x+101\right)=0$

$x-10=0$

$x=10$

(b)

we are given volume

so, we can set

$V=14\frac{5}{8}=\frac{14\times 8+5}{8}$

$V=\frac{117}{8}$

and then we can solve for x

$V=x^3+x^2-9x-9=\frac{117}{8}$

now, we can factor it

$8x^3+8x^2-72x-189=0$

$\left(2x-7\right)\left(4x^2+18x+27\right)=0$

$2x-7=0$

$x=\frac{7}{2}$

8 0

4 years ago

Simplify the following expression -5[(x^3+1)(x+4)]

katrin [286]

Answer:

B

Step-by-step explanation:

-5[ (x³+1)(x+4) ] = -5[ x³*(x+4) + 1*(x+4) ]

= -5 [ x³*x + x³*4 + 1*x + 1*4 ]

= -5 [ x⁴ + 4x³ + x + 4]

= -5*x⁴ + (-5)*4x³ + (-5)*x + (-5) * 4

= -5x⁴ - 20x³ - 5x - 20

4 0

3 years ago

Select the function that's represented in the graph. Question 5 options: A) ƒ(x) = x2 – 3 B) ƒ(x) = –1∕2x2 – 3 C) ƒ(x) = –x2 – 3

Neporo4naja [7]

Answer:

a)

Step-by-step explanation:

hello,

because of the end behaviour the constant in $x^2$ should be positive so we have a) or d)

f(0)=-3 in both cases

for A) f(x)=

$x^2-3=(x-\sqrt{3})(x+\sqrt{3})$

so f(x)=0 for $x=\sqrt{3} \ or \ x = -\sqrt{3}$

so the correct answer is A)

hope this helps

3 0

3 years ago