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Soloha48 [4]
3 years ago
5

How many times larger is 2 x 10-6 than 2 x 10-11? A) 1 x 104 B) 1 x 105 C) 2 x 104 D) 2 x 105

Mathematics
1 answer:
Liula [17]3 years ago
8 0
The answer to this problem is B. 1x105
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Factor by grouping<img src="https://tex.z-dn.net/?f=%284y%5E3%20%2B%2028y%5E2%29%20%2B%20%28y%20%2B%207%29" id="TexFormula1" tit
Inessa05 [86]

We have the following expression given:

(4y^3+28y^2)+(y+7)

We can start selecting as common factor 4y^2 and we got:

4y^2(y+7)+(y+7)

Now we can select y+7 as common factor and we got:

(y+7)\left\lbrack 4y^2+1\right\rbrack

So then our final answer would be:

(y+7)(4y^2+1)

3 0
1 year ago
Approximate the square root of 500 to the nearest tenth. Show your work.
bulgar [2K]
\sqrt{500} \rightarrow \sqrt{5 * 10 * 10} \rightarrow 10\sqrt{5} This is an exact answer. the answer will be a bit larger than 20
4 0
3 years ago
1. Complete the inequality below to describe the
dezoksy [38]

Domain is the entire span left to right (on the x-axis) that the graph is on. Since the graph goes from x=-4 and ends at x=4, the domain would be from -4 to 4. The circle at -4 is open, so it does not include the point at -4, just everything leading up to it. So, the domain would be

- 4 < x \leqslant 4

The range is similar, it is the entire span that the graph goes up and down (on the y-axis). The graph starts at the bottom at y=-2, and ends at y=5. The bottom point (4,-2) is closed, so the graph includes that point, and the top point (-4,5) is open and doesn't include the point. Therefore, the range would be

- 2 \leqslant x < 5

5 0
3 years ago
Read 2 more answers
Help its due in 5 mins lol
inessss [21]
Y= 26 & x=35 hope I did it on time!
6 0
3 years ago
4x-11y=68 ; 6x+5y=-27 by elimination
zimovet [89]

Answer:

x=\frac{1}{2}\\\\y=-6

Step-by-step explanation:

Given the following system of equations:

\left \{ {{4x-11y=68} \atop {6x+5y=-27}} \right.

In order to solve the system of equations using the Elimination Method, you can follow these steps:

- Multiply the first equation by -6 and the secondd equation by 4.

- Add both equations.

- Solve for "y".

Then:

\left \{ {{-24x+66y=-408} \atop {24x+20y=-108}} \right\\.........................\\86y=300\\\\y=\frac{-516}{86}\\\\y=-6

- Substitute the value of "y" into one of the original equations and solve for "x":

6x+5(-6)=-27\\\\6x=-27+30\\\\x=\frac{3}{6}\\\\x=\frac{1}{2}

4 0
3 years ago
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