Consider the following reversible reaction l. 2H2Og 2H2g+O2g what is the equilibrium constant expression for the given system?
1 answer:
Answer:
The equilibrium consntant expression is:
Keq= (02) x (H2)^2/(H20)^2
Explanation:
The equilibrium constant is calculated as the ratio between products and reagents raised to their stoichiometric coefficients. In this case, Water (H20) is a reagent and the respective products are Hydrogen (H2) and Oxygen (02)
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