the equilibrium concentration of H₂(g) at 700°C = 0.00193 mol/L
0.00193 mol/L
Given that:
numbers of moles of H₂S = 0.59 moles
Volume = 3.0-L
Equilibrium constant = 9.30 × 10⁻⁸
The equation for the reaction is given as :
2H₂S ⇄ 2H₂(g) + S₂(g)
The initial concentration of H₂S =
The initial concentration of H₂S =
= 0.1966 mol/L
The ICE table is shown be as :
2H₂S ⇄ 2H₂(g) + S₂(g)
Initial 0.9166 0 0
Change -2 x +2 x + x
Equilibrium (0.9166 - 2x) 2x x
(since 2x < 0.1966 if solved through quadratic equation)
The equilibrium concentration for H₂(g) = 2x
∴
= 0.00193 mol/L
Thus, the equilibrium concentration of H₂(g) at 700°C = 0.00193 mol/L
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Answer:
The binding energy released is 1.992 X 10⁻¹⁸ J
Explanation:
Given;
mass of the alpha particle, m = 6.64 x 10⁻²⁷ kg
speed of the alpha particle, c = 3 x 10⁸ m/s
The binding energy released is given by;
where;
m is mass of the particle
c is speed of the particle
E = 6.64 x 10⁻²⁷ (3 x 10⁸)²
E = 1.992 X 10⁻¹⁸ J
Therefore, the binding energy released is 1.992 X 10⁻¹⁸ J
Answer:
anaphase
Explanation:
because the chromosomes are moving towards different poles
Answer: option <span>B.The total mass of A and C, which are carbon and oxygen, is equal to the mass of B, which is carbon dioxide.
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Explanation:
1) The combustion of carbon is represented by the chemical equation:
C + O₂ → CO₂
2) The law of conservation of mass states that the mass of the products is equal to the mass of the reactants.
3) The reactants are C and O₂, while the product is CO₂.
4) The masses given are: A: 12 g, B: 44 g, and C: 32 g
Then, 12g + 32 g = 44 g, this is A + C = B.
Then, B represents the product, which is CO₂, whose molar mass is 44 g/mol.
Since, the molar mass of C is 12 g/mol, it is A; and since the molar mass of O₂ is 32, it is C.
Therefore, the answer is the option B.
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