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kirill115 [55]
3 years ago
6

What are the counting numbers in base 6

Mathematics
1 answer:
WITCHER [35]3 years ago
8 0

In the base 6 number system, we would only use numerals from 0 to 5. The idea of base 6 is just like the normal base 10 system, however instead of using the numerals from 0 to 9, we use numerals from 0 to 5. And instead of having a ones digit, a tens digit, a hundreds digit and so on, we use a ones digit, a sixes digit, a thirty-sixes digit, and so on. Therefore in base 6, the number 321 means 1  one plus 2 sixes plus 3 thirty-sixes, or 121. So to count until 15 for example, we  would need:

 

Base 6                                                                   Base 10

 

1                                                                                  1   

2                                                                                  2

3                                                                                  3

4                                                                                  4

5                                                                                  5

10  (1 six plus 0 ones)                                                 6

11  (1 six plus 1 one)                                                   7

12  (1 six plus 2 ones)                                                 8

13                                                                                9

14                                                                              10

15                                                                              11

20  (2 sixes plus 0 ones)                                           12

21  (2 sixes plus 1 one)                                             13

22                                                                              14

23                                                                              15

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Part b) The function’s equation written in factored form is equal to

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Step-by-step explanation:

Part a) What is the function’s equation written in vertex form?

we know that

The equation of a vertical parabola written in vertex form is equal to

f(x)=a(x-h)^2+k

where

a is a coefficient

(h,k) is the vertex

Looking at the graph

The vertex is the point (2,-8)

substitute

f(x)=a(x-2)^2-8

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therefore

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f(x)=2(x-2)^2-8

Part b) What is the function’s equation written in factored form?

we know that

The equation of a vertical parabola written in factored form is equal to

f(x)=a(x-x_1)(x-x_2)

where

a is a coefficient

x_1 and x_2 are the zeros or x-intercepts of the function

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Looking at the graph

The zeros or x-intercepts of the function are

x=0 and x=4

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therefore

The function’s equation written in factored form is equal to

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