If you roll two number cubes what is the probability of rolling two sixes

Mrrafil [7]

Answer:

The shape has a total area of 14.96cm²

Step-by-step explanation:

To solve this all you need to do is take the area of the outer rectangle, and subtract the area of the inner rectangle.

The outer rectangle is 5.6 by 6.4 cm. To get its area, just multiply those dimensions. When you do so you get the area 35.84cm².

Next the inner rectangle needs to be subtracted. First though, we need its width, which we're not directly given.

We do however know the width of the entire shape, and the width of segments left after cutting out the inner rectangle. All we need to do then is subtract the later from the former to the the inner rectangle's width:

5.6cm - 1.2cm - 0.8cm = 3.6cm

Great! The inner rectangle has an area of 3.6cm × 5.8cm. That gives us 20.88cm².

The final step is to subtract that 20.88 square cm from the 35.84 that we already have. Doing so gives us a result of 14.96cm², and that is the final answer.

5 0

2 years ago

Read 2 more answers

Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = n

ziro4ka [17]

These 2 equations has no solution and the equations are independent of each other.

<u>Step-by-step explanation:</u>

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

4 0

3 years ago

Read 2 more answers

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago

a cylindrical well has a radius of 10 feet and a height of 15 feet what volume of water will it take to fill in the well

vampirchik [111]

Volume of water will it take to fill in the well is 4710 cubic feet

<h3><u>Solution:</u></h3>

Given that a cylindrical well has a radius of 10 feet

Height of cylindrical well = 15 feet

To find: volume of water will it take to fill in the well

Since, the well is in the form of cylinder, This means that we need to find the volume of cylindrical well

<em><u>The volume of cylinder is given as:</u></em>

$\text { Volume of water in the well }=\pi r^{2} h$