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7nadin3 [17]
3 years ago
7

GIVE THE RIGHT ANSWER AND PROVE THAT ITS RIGHT

Mathematics
2 answers:
Lunna [17]3 years ago
5 0

The right answer is 56

SSSSS [86.1K]3 years ago
3 0

a = 56

given 28 = \frac{1}{2} a

multiply both sides by 2 to eliminate the fraction

56 = a

As a check

\frac{1}{2} × 56 = 28 ← True


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The solution to the equation is x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

Explanation:

Given that the equation is -x^2+5x-3=0

We need to determine the solution of the equation.

The solution of the equation can be determined using the quadratic formula.

The quadratic formula is given by

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Hence, from the equation, we have,

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Substituting these values in the quadratic formula, we get,

x=\frac{-5\pm \sqrt{5^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)}

Simplifying, we get,

x=\frac{-5\pm \sqrt{25-12}}{-2}

Simplifying the terms within the root, we get,

x=\frac{-5\pm \sqrt{13}}{-2}

Thus, the roots of the equation are x=\frac{-5+ \sqrt{13}}{-2} and x=\frac{-5- \sqrt{13}}{-2}

Taking out the negative sign, we get,

x=\frac{-(5- \sqrt{13})}{-2} and x=\frac{-(5+ \sqrt{13})}{-2}

Cancelling the negative sign, we get,

x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

Thus, the solutions of the equation are x=\frac{5-\sqrt{13}}{2} and x=\frac{5+\sqrt{13}}{2}

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Answer:

45

Step-by-step explanation:

7 0
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