Ask question

Ask question

All categories

Alexeev081 [22]

3 years ago

15

What is the value of 1 raised to a negative exponent?

1 answer:

Vinil7 [7]3 years ago

5 0

Answer:

its whatever the exponent is

Step-by-step explanation:

You might be interested in

Parker bought a 15-year treasury bond for a face amount of $400. The 3.5% interest will be compounded quarterly. What will the f

MArishka [77]

If you're behind like I am and are just now doing these assignments then good luck on catching up.

If it's AQRB Unit 2 Lesson 3 then the answers to the multiple choice are below, you'll need to do the essay and calculation on your own.

1: $674.64
2: $26, 255.38
3: $191, 398.49
4: $23, 884.84

6 0

4 years ago

Jorge ordered 22 bottles of juice. Each bottle holds 6.32 ounces of juice.

Umnica [9.8K]

Answer: On the first one its either A or D. (I think)

Step-by-step explanation:

So what I did was I multiplied 22 and 6.32 together and got 139.04 and the closest estimate to that would be 160 because 39 is closer to 60 than 20 (A) and since its not 150 the estimate would be lower than higher. (D)

4 0

3 years ago

Read 2 more answers

A super clearance sale, bathing suits were marked 85% off. What is the sale price of a bathing suit that was originally priced $

liraira [26]

Answer: 9$
Explanation: 15% is how much a person will pay and 15% of 60 is 9$

5 0

3 years ago

Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.

Irina18 [472]

Answer:

<u>TO FIND :-</u>

Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$
$\tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}$

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

$=> \sin 16 = \frac{7}{x}$

$=> \frac{7}{x} = 0.27563......$

$=> x = \frac{7}{0.27563....} = 25.39568.....$ ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

$=> \sin 29 = \frac{6}{x}$

$=> \frac{6}{x} = 0.48480......$

$=> x = \frac{6}{0.48480....} = 12.37599.....$ ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

$=> \sin 30 = \frac{x}{11}$

$=> \frac{x}{11} = 0.5$

$=> x = 0.5 \times 11 = 5.5$

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

$=> \cos 43 = \frac{x}{12}$

$=> \frac{x}{12} = 0.73135......$

$=> x = 12 \times 0.73135.... = 8.77624....$ ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

$=> \cos 55 = \frac{x}{6}$

$=> \frac{x}{6} = 0.57357......$

$=> x = 6 \times 0.57357.... = 3.44145....$ ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

$=> \cos 73 = \frac{8}{x}$

$=> \frac{8}{x} = 0.29237......$

$=> x = \frac{8}{0.29237.....} = 27.36242.....$ ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

$=> \tan 69 = \frac{12}{x}$

$=> \frac{12}{x} = 2.60508......$

$=> x = \frac{12}{2.60508....} = 4.60636....$ ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

$=> \tan 20 = \frac{11}{x}$

$=> \frac{11}{x} = 0.36397......$

$=> x = \frac{11}{0.36397....} =30.22225....$ ≈ 30.2

5 0

3 years ago

Help i can’t find this answer anywhere.

murzikaleks [220]

Answer:

B, I think that's the answer

6 0

3 years ago