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3 years ago

How do I plot these on the number line?? Answers quick!

Mathematics

1 answer:

maw [93]3 years ago

3 0

Convert them into fractions
i)-2 3/8 = -19/8
ii)0.75 = 75/100 = 3/4
iv) 1 3/4 = 7/4
Now convert all of them in the form of p/q where q = 8
Therefore
ii)6/8
iv) 14/8

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Use two unit multipliers to convert 1500 centimeters to feet. thanks :)

bagirrra123 [75]

49.2126 Feet (ft)

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3 years ago

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The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

2 years ago

The distance between the points (12,9) and (0,4) is A) 14 units B) 13 units C) 15 units D) 16 units

Juliette [100K]

Answer:

Option B 13 units is correct.

Step-by-step explanation:

The formula used to find distance between 2 points is:

$d(P1,P2)=\sqrt{(x_{2} -x_{1})^2 + (y_{2} -y_{1})^2 }$

x₁ = 12 x₂ = 0 y₁= 9 and y₂=4

Putting values in the formula:

$=\sqrt{(0-12)^2+(4-9)^2}\\=\sqrt{(-12)^2+(-5)^2}\\=\sqrt{144+25} \\=\sqrt{169} \\=13$

So, Option B 13 units is correct.

6 0

2 years ago

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At the last minute, the technology company decides to expand the warehouse and asks the general contractor to double the dimensi

Lesechka [4]

The expansion of the warehouse will not affect the dimensions of the surrounding fence.

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3 years ago

A student is attempting to factor a polynomial. Sample mathematical work is shown below. Which statement best applies to the sam

Vladimir [108]

The choices are:

A. The student identified the greatest common factor incorrectly.
B. The student incorrectly divided each term by the greatest common factor.
C. The student failed to simplify the expression.
D. The mathematical work shown is correct.

I think the correct answer from the choices is option D. The mathematical work shown is correct. Hope this answers the question. Have a nice day.

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2 years ago