<h2> first say me plz which language is this</h2>
Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:

Step-by-step explanation:
Since the line goes through the origin and is propotinal, we just do y/x
4/3= 1 1/3
y=1 1/3x
CHECK (Using desmos)
T=2n+3
considering n has no other values given
Answer:
The answer is (2, 4)
Step-by-step explanation:
I hope this helps!