let the weight of the second alloy be y convert the percentage to fraction, that is 10/100=0.1, 18/100=0.18, 13/100=0.13 Total weight if the mixture is 0.1 x 25+0.18y=0.13(25+y) 2.5+0.18y=3.25+0.13y like terms together 0.18y +0.13y = 3.25-2.5 0.05y=0.75 divide both side by 0.05 Y is therefore 15 pound of 18% copper is needed
1000 is our constant because the truck was only used one day. We also know they charge a certain amount per hour, but we do not know how much. In this case they charged that amount 9 times because the truck was used for 9 hours. The total of the constant plus the 9hour fee is 2700 dollars:
1000(1) + 9x = 2700
The reason we multiply 1000 by 1, is because we only used the truck for one day.
Solve for x
9x = 2700 - 1000 = 1700
X = 1700/9 = 188.88
The hourly fee is $188.88 The question is asking for an equation for hours of use though, so the answer is
