An alloy of copper is 10% copper and weighs 25 pounds. A second alloy is 18% copper. How much (to the nearest tenth lb.) of the
1 answer:
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Answer:
B. y=1/3x+4
Step-by-step explanation:
Hi there!
We are given the line PQ and we want to find the line that is perpendicular to it
Perpendicular lines have slopes that are negative and reciprocal. When they are multiplied together, the result is -1
So first, let's find the slope of the line PQ
The point P is given as (-8, 7) and the point Q is given as (-4, -5)
The formula for the slope calculated from two points is where (
) and (
,
) are points
We have the needed information for the slope, but let's label the values of the points to avoid any confusion
x1=-8
y1=7
x2=-4
y2=-5
Now substitute into the formula (m is the slope, and remember: the formula contains SUBTRACTION):
m=
simplify
m=
add
m=-12/4
divide
m=-3
So the slope of the line PQ is -3
As said above, perpendicular lines have slopes that have a product of -1
So to find the slope of the line perpendicular to PQ, use this formula:
-3m=-1
divide both sides by -3
m=1/3
The only line that has a slope of 1/3 is B (y=1/3x+4), so B is the answer.
Hope this helps!