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4 years ago

What is the center and radius of the circle with equation (x - 2)2 + (y - 5)2 = 100?

Mathematics

2 answers:

timama [110]4 years ago

3 0

Answer:

Center = (2, 5) and radius = 10

Step-by-step explanation:

The general form of the equation of a circle with center (a, b) and radius r is:-

(x - a)^2 + (y - b)^2 = r^2

So comparing this with our equation

(x - 2)^2 + (y - 5)^2 = 100

we see that the center is (2, 5) and radius = 10

Gnesinka [82]4 years ago

3 0

Answer:Center:2,5

Radius:10

Step-by-step explanation:

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Ax = bx + 1. How is the value of x related to the difference of a and b?

Zielflug [23.3K]

Answer:

x = 1/(a-b)

Step-by-step explanation:

The given equation is ax = bx + 1

Collecting like terms:

ax - bx = 1

Factorizing x out of the equation:

x(a - b) = 1

Dividing both sides by (a - b):

$\frac{x(a - b)}{(a - b)} = \frac{1}{a - b} \\x = \frac{1}{a - b}$

Therefore, x is related to the difference of a and be by the equation

x = 1/(a-b) where a - b is the difference of a and b

7 0

3 years ago

Read 2 more answers

You insurance policy on your car costs $600 a year. If you total your vehicle, you insurance company will pay $25,000 towards a

vladimir2022 [97]

Answer:

Your annual expected value is -$550.

Step-by-step explanation:

0.002 probability that you will total your car.

If you total your car, you pay the insurance of $600, but you get the $25,000 insurance. So in total, the net value will be $24,400.

1-0.002 = 0.998 probability that you will not total your car.

In this case, you lose $600.

What is your annual expected value?

Multiply each net value by it's probability.

E = 0.002*24400 - 0.998*600 = -550

Your annual expected value is -$550.

4 0

3 years ago

Given h(x) = 2x - 3 , solve for when h(x) = - 3 .

FrozenT [24]

Answer:

h(x)=-3;x=0

Step-by-step explanation:

When given h(x), you are in effect, being given the output of the function.

So, placing h(x)=-3 in place for h(x)

We get

-3=2x-3

Where -3+3=2x

0=2x

x=0

So, x=0

8 0

3 years ago

Why does stock have more potential for higher returns than bonds?

morpeh [17]

Answer:

Stocks have historically delivered higher returns than bonds because there is a greater risk that, if the company fails, all of the stockholders' investment will be lost.

Step-by-step explanation:

Hope this will help

7 0

4 years ago

Pleeease open the image and hellllp me

Verdich [7]

1. Rewrite the expression in terms of logarithms:

$y=x^x=e^{\ln x^x}=e^{x\ln x}$

Then differentiate with the chain rule (I'll use prime notation to save space; that is, the derivative of y is denoted y' )

$y'=e^{x\ln x}(x\ln x)'=x^x(x\ln x)'$

$y'=x^x(x'\ln x+x(\ln x)')$

$y'=x^x\left(\ln x+\dfrac xx\right)$

$y'=x^x(\ln x+1)$

2. Chain rule:

$y=\ln(\csc(3x))$

$y'=\dfrac1{\csc(3x)}(\csc(3x))'$

$y'=\sin(3x)\left(-\cot^2(3x)(3x)'\right)$

$y'=-3\sin(3x)\cot^2(3x)$

Since $\cot x=\frac{\cos x}{\sin x}$ , we can cancel one factor of sine:

$y'=-3\dfrac{\cos^2(3x)}{\sin(3x)}=-3\cos(3x)\cot(3x)$

3. Chain rule:

$y=e^{e^{\sin x}}$

$y'=e^{e^{\sin x}}\left(e^{\sin x}\right)'$

$y'=e^{e^{\sin x}}e^{\sin x}(\sin x)'$

$y'=e^{e^{\sin x}+\sin x}\cos x$

4. If you're like me and don't remember the rule for differentiating logarithms of bases not equal to e, you can use the change-of-base formula first:

$\log_2x=\dfrac{\ln x}{\ln2}$