Question

In a survey of a town, 56% of residents own a car, 21% of residents now a truck, and 4% of residents own both a car and a truck. What is the conditional probability that a person also owns a truck, given that they own car? Round to the nearest whole percent.

Answer 1

4.6 rounded to whole number would be 5%

Answer 2

Answer:

$P(A given B)=0.190$

Step-by-step explanation:

It is given that In a survey of a town, 56% of residents own a car, that is P(A)=0.56

21% of residents now a truck, that is P(B)=0.21

and 4% of residents own both a car and a truck that is P(A∩B)=0.04

Now, the conditional probability that a person also owns a truck, given that they own car is:

$P(A given B)=\frac{P(A{\cap}B)}{P(B)}$

$P(A given B)=\frac{0.04}{0.21}$

$P(A given B)=0.190$

Thus, the conditional probability that a person also owns a truck, given that they own car is 0.190.