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Stells [14]
4 years ago
5

If 840. mL of linseed oil has a mass of 700. g, calculate the density of linseed oil.

Chemistry
1 answer:
aleksklad [387]4 years ago
6 0

Density can be determined as:

d = m /V

whereas, m is mass of compound

v is volume

d = 700 /840 = 0.83 g /mL

Thus density is 0.83 g /mL


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A lake in California contains about 8,500,000,000,000 gallons of water. How can this
aniked [119]

Answer:

8.5 * 10^11

Explanation:

8 0
3 years ago
How many grams of magnesium<br> sulfate (MgSO4) are dissolved in<br> 0.965 L of a 0.0575 M solution?
JulsSmile [24]
<h3>Answer:</h3>

6.68 g MgSO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.965 L

0.0575 M

<u>Step 2: Identify Conversions</u>

Molar Mass of Mg - 24.31 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol

<u>Step 3: Find MgSO₄</u>

  1. Substitute [M]:                     0.0575 M = x / 0.965 L
  2. Isolate <em>x</em>:                              0.055488 mol MgSO₄ = x
  3. Rewrite:                               x = 0.055488 mol MgSO₄

<u>Step 4: Convert</u>

<u />\displaystyle 0.055488 \ mol \ MgSO_4(\frac{120.38 \ g \ MgSO_4}{1 \ mol \ MgSO_4} ) = 6.67959 g MgSO₄

<u>Step 5: Check</u>

<em>We are given 3 sig figs as our lowest. Follow sig fig rules and round.</em>

6.67959 g MgSO₄ ≈ 6.68 g MgSO₄

5 0
3 years ago
N2 + 3H2 Right arrow. 2NH3 What is the percent yield of NH3 if the reaction of 26.3 g of H2 produces 79.0 g of NH3? Use Percent
Romashka [77]

Answer:

53.4%

Explanation:

N₂ + 3H₂ → 2NH₃

Given that:

26.3 g of H₂ react with N₂ to produce 79.0 g of NH₃

Then:

The number of moles of H₂ = 26.3g of H₂ * (1 mol of H₂/ 2.02g of H₂)

= 13.05 mol of H₂

The number of moles of NH₃ = 13.05 mol of H₂ * ( 2mol of NH₃/ 3 mol of H₂)

= 8.697 mol of NH₃

The mass of NH₃ = 8.697 mol of NH₃ *( 17.04g of NH₃/ 1 mol of NH₃) = 148.1 g of NH₃

The percent yield = actual yield/ theoretical yield * 100%

The percent yield = ( 79.0 g/ 148.1 g )* 100%

The percent yield ≅ 53.4 %

7 0
3 years ago
Read 2 more answers
An 1.04-L sample of gas at 759 mm Hg pressure
telo118 [61]

PV = nRT

where P is the pressure,

V is the volume,

n is the moles of gas,

R is the gas constant,

and T is the temperature.

We must relate this equation to a sample of gas at two different volumes however. Looking at the equation, we can relate the change in volume by:

P1V1 = P2V2

where P1 is the initial pressure,

V1 is the initial volume,

P2 is the final pressure,

and V2 is the final volume.

Looking at this relationship, pressure and volume have an indirect relationship; when one goes up, the other goes down. In that case, we can use this equation to solve for the new pressure.

P1V1 = P2V2

(759 mm Hg)(1.04 L) = P2(2.24 L)

P2 = 352 mm Hg (rounded to three significant figures)

8 0
4 years ago
What is the warmest layer of the atmosphere?
Lemur [1.5K]

Answer:

Explanation:

The thermosphere is often considered the "hot layer" because it contains the warmest temperatures in the atmosphere. Temperature increases with height until the estimated top of the thermosphere at 500 km. Temperatures can reach as high as 2000 K or 1727 ºC in this layer (Wallace and Hobbs 24).

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3 years ago
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