What is the identity of the element with the electron configuration of
1 answer:
You might be interested in
Answer : The percent abundance of the heaviest isotope is, 78 %
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
As we are given that,
Average atomic mass = 48.68 amu
Mass of heaviest-weight isotope = 49.00 amu
Let the percentage abundance of heaviest-weight isotope = x %
Fractional abundance of heaviest-weight isotope =
Mass of lightest-weight isotope = 47.00 amu
Percentage abundance of lightest-weight isotope = 10 %
Fractional abundance of lightest-weight isotope =
Mass of middle-weight isotope = 48.00 amu
Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %
Fractional abundance of middle-weight isotope =
Now put all the given values in above formula, we get:
Therefore, the percent abundance of the heaviest isotope is, 78 %
Answer:
Two moles.
Explanation:
Sulphuric (sulfuric) acid is a diprotic acid. When one mole of
molecules dissolve in water, two moles of
ions would be produced.
.
On the other hand, sodium hydroxide is a monoprotic base. When one mole of
formula units dissolve in water, only one mole of hydroxide ions
would be produced.
.
Note that and
react at a one-to-one ratio:
.
As a result, it would take of
to react with the
of
that was released when
of
is dissolved in water. Since one mole of
formula units could produce only one mole of
, it would take
of
formula units to produce that
of
for reacting with
of
.