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slavikrds [6]
3 years ago
7

Simplify 7x+21/x2+5x+6 divided by x+6/x+2 A. 7/x+6 B. 4x(x+7)/x+10 C. 10/x+7 D. 7/5

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0
The answer is A.  And here's how you get it.  You start by simplifying between the numerator and the denominator in the top fraction. Factor the top and the botttom so you have this: [7(x+3)/(x+3)(x+2)]/[(x+6)/(x+2)].  The (x+3)'s in the top fraction cancel each other out leaving you with [7/(x+2)]/[(x+6)/(x+2)].  When you divide fractions by fractions you change the sign and flip the fraction in the denominator so now you have this: [7/(x+2)]*[(x+2)/(x+6)]. The (x+2)'s cancel each other out then leaving you with 7/(x+6)
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viva [34]

Answer:

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Step-by-step explanation:

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8 0
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Goshia [24]

Answer:

  35

Step-by-step explanation:

The equations will be "consistent" when they describe lines that are not parallel.

<h3>Slopes</h3>

The slope of a line whose equation is written in this form is the opposite of the ratio of the y-coefficient to the x-coefficient:

  line 1 slope = -8/20 = -2/5

  line 2 slope = -14/35 = -2/5

These lines have the same slope, so will be parallel unless they have the same y-intercept.

<h3>Y-intercept</h3>

The y-intercept of each line is the ratio of the constant to the y-coefficient:

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  line 2 y-intercept = k/35

We want these lines to have the same y-intercept so that they are not inconsistent. This requires ...

  k/35 = 1

  k = 35

For the equations to be consistent, we must have k = 35.

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<em>Additional comment</em>

Linear equations are generally categorized as "consistent" or "inconsistent," and "dependent" or "independent."

Equations are "inconsistent" if there are no values of the variables that satisfy all of the equations. They are "dependent" if they describe exactly the same relation between the variables. "Consistent" equations may be "dependent" (describing the same line, as here), or "independent" (describing lines with different slopes.)

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B. 16.30 = 16.3

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What is 5330 divided by 65
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The answer is 82. hope this helps!

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