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SIZIF [17.4K]
3 years ago
5

If a < 0 and c > b, circle the expression that is greater:

Mathematics
1 answer:
matrenka [14]3 years ago
5 0

Answer:

The expression that is greater is a (b - c)

Step-by-step explanation:

  • a < 0 and c > b, this means <u>(by the addition property)</u> that c - c > b - c⇒0 > b - c

so for the product <u>a(b - c) </u>we would have a multiplication of a negative number <em>a</em> and another negative number <em>(b - c)</em>. We know that the result of the <u>multiplication of two negative numbers  is a positive number.</u>

Therefore, a (b - c) > 0

  • a < 0 and c > b, this means <u>by the addition property</u> that c - b > b - b⇒ c - b > 0

so for <u>a(c - b)</u>, we have the negative number <em>a</em> multiplied by the positive number <em>(c - b). </em>We know that the result of the <u>multiplication of a negative number by a positive number is negative. </u>

<u>Therefore  a (c - b) < 0</u>

Thus, the expression that is greater is the positive one which is a (b - c)

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(t-5)=5(t-5)+8 I need the steps to solve also
Afina-wow [57]

Answer:

t = 3

Step-by-step explanation:

\tt (t-5)=5(t-5)+8

1) Expand

\tt t-5=5t-17

2) Add 5 to both sides

\tt t -5+5=5t-17+5

\tt t=5t-12

3) Subtract 5t from both sides

\tt t-5t=5t-12-5t

\tt -4t=-12

4) Divide both sides by -4

\tt \cfrac{-4t}{-4}=\cfrac{-12}{-4}

\tt t=3

Hope it helps! :)

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Step-by-step explanation:

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