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Lostsunrise [7]
3 years ago
10

Write 129.701 in expanded form

Mathematics
2 answers:
Irina-Kira [14]3 years ago
7 0
129.701 in expanded form:

100 + 20 + 9 + (7 x 1/10) + (1 x 1/1000)

1 is in the hundreds place      so 1 x 100 =       100
2 is in the tens place              so 2 x   10 =         20
9 is in the ones place             so 9 x     1 =           9
7 is in the tenths place           so 7 x      1/10 =     0.7
1 is in the thousandths place so 1 x      1/1000 = 0.001
ruslelena [56]3 years ago
4 0
100+20+9+.700+.001 is 129.701 in expanded form.
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Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0
2 years ago
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4 years ago
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2 years ago
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Step-by-step explanation:

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2 years ago
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The question is incomplete. The table missing is attached.

Answer:

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4 years ago
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