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Akimi4 [234]
3 years ago
5

Can somebody help with this I will mark you brainly. please show your work

Mathematics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

4.5

Step-by-step explanation:

360 divided by 80 = 4.5

galina1969 [7]3 years ago
7 0

Answer:

4.5 hours

Step-by-step explanation:

80 mph means that each hour 80 miles were driven

so you can do 360 / 80 = 4.5

proof 80 miles * 4.5 hours = 360 miles

Hope this helps!

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What is the answer to 2+4×7
PIT_PIT [208]
2+4×7=
=2+28=30
Answer: 30
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4 years ago
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Which, if any, pair of sides are parallel? AB II DC and AD II BC Cannot be determined AB II DC only AD II BC only
zaharov [31]

Answer:

120%

Step-by-step explanation:

5 0
3 years ago
Which equation represents the magnitude of an
Basile [38]

Answer:

M=\log{(100S)}

Step-by-step explanation:

The <em>Richter scale</em>, the standard measure of earthquake intensity, is a <em>logarithmic scale</em>, specifically logarithmic <em>base 10</em>. This means that every time you go up 1 on the Richter scale, you get an earthquake that's 10 times as powerful (a 2.0 is 10x stronger than a 1.0, a 3.0 is 10x stronger than a 2.0, etc.).

How do we compare two earthquake's intensities then? As a measure of raw intensity, let's call a "standard earthquake" S. What's the magnitude of this earthquake? The magnitude is whatever <em>power of 10</em> S corresponds to; to write this relationship as an equation, we can say 10^m=S, which we can rewrite in logarithmic form as m=\log{S}.

We're looking for the magnitude M of an earthquake 100 times larger than S, so reflect this, we can simply replace S with 100S, giving us the equation

M=\log{(100S)}.

To check to see if this equation is right, let's say we have an earthquake measuring a 3.0 on the Richter scale, so 3=\log{S}. Since taking 100 times some intensity is the same as taking 10 times that intensity twice, we'd expect that more intense earthquake to be a 5.0. We can expand the equation M=\log{(100S)} using the product rule for logarithms to get the equation

M=\log{(100S)}=\log{100}+\log{S}

And using the fact that \log{100}=2 and our assumption that \log{S}=3, we see that M=2+3=5 as we wanted.

3 0
4 years ago
I need the solution
Nataly [62]

The only thing you can do here is to try to simplify, so I'll assume that's what you want to do.

\dfrac{b^2-a^2}{2a^2+ab-3b^2}

The numerator is a difference of squares, so it's easy to factorize:

b^2-a^2=(b-a)(b+a)

In the denominator, we factorize by grouping:

2a^2+ab-3b^2=2a^2-2ab+3ab-3b^2=2a(a-b)+3b(a-b)=(2a+3b)(a-b)

So we have

\dfrac{b^2-a^2}{2a^2+ab-3b^2}=\dfrac{(b-a)(b+a)}{(2a+3b)(a-b)}=-\dfrac{b+a}{2a+3b}

5 0
4 years ago
What is the dependent quantity?
den301095 [7]

Answer?: I believe its C

No Explanation Because No

4 0
3 years ago
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