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diamong [38]
3 years ago
8

Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $22 monthly fee

and charges an additional $0.07 for each minute of calls. The second plan has an $8 monthly fee and charges an additional $0.12 for each minute of calls. For how many minutes of calls will the costs of the two plans be equal?
Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
Company a = 22 + 0.07m
company b = 8 + 0.12m

We are looking for the time when the prices are equal. i.e. the price of company a = the price of company b

company a = company b
22 + 0.07m = 8 + 0.12m
22 - 8 = 0.12m - 0.07m
14 = 0.05m
m = 14/0.05
m = 280

Therefore, the two companies will cost the same if you talk for 280 minutes
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Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

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Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = ^{6}C_{1}\times^{4}C_{3}=6\times4=24

2 Boy and 2 girls=^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90

3 Boys and 1 girl = ^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80

4 Boys = ^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15

Now total number of ways = 24 + 90 + 80 + 15 = 209

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