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What three consecutive integers have a sum of 48? Which means that the first number is 15, the second number is 15 + 1 and the third number is 15 + 2. Therefore, three consecutive integers that add up to 48 are 15, 16, and 17.
Answer:
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Step-by-step explanation:
1- Let's solve the numerator Inside the bracket m⁻¹.m⁵ =m⁽⁻¹⁺⁵⁾ =m⁽⁴⁾
2- numerator/denominator = m⁽⁴⁾ / m⁻² = m⁽⁴⁾⁻⁽⁻²⁾ =m⁶
3- Now let' include it in the parenthesis:[ m⁶]⁻³ =m⁻¹⁸ =1/m¹⁸<u />
