A faulty communication line for digital signals flips 25% of the 0's to 1's and 1/3 of the 1's to 0's. if 40% of a particular fi
le being transmitted consists of 0's and 60% consists of 1's, what is the probability that when a 0 is received it was transmitted correctly (i.e., a 0 was transmitted)?
1 answer:
I find it helpful to put the given information into a chart. It shows the probability of receiving a 0 is 50%, and that when a 0 is received, 30% of the time a 0 was sent and 20% of the time a 1 was sent.
Hence ...
P(sent 0 | received 0) = P(sent 0 & received 0) / P(received 0)
P(sent 0 | received 0) = 0.30/0.50 = 3/5 = 0.60
You might be interested in
Given:
The point is (6,2).
To find:
The image of given point after rotation of 270 degrees.
Solution:
Let the given point be P(6,2).
Rotation of 270 degrees means the figure is rotated 270 degrees counterclockwise about the origin. So, the rule of rotation is
Using this rule, we get
Therefore, the image of given point is (2,-6).