A faulty communication line for digital signals flips 25% of the 0's to 1's and 1/3 of the 1's to 0's. if 40% of a particular fi
le being transmitted consists of 0's and 60% consists of 1's, what is the probability that when a 0 is received it was transmitted correctly (i.e., a 0 was transmitted)?
1 answer:
I find it helpful to put the given information into a chart. It shows the probability of receiving a 0 is 50%, and that when a 0 is received, 30% of the time a 0 was sent and 20% of the time a 1 was sent.
Hence ...
P(sent 0 | received 0) = P(sent 0 & received 0) / P(received 0)
P(sent 0 | received 0) = 0.30/0.50 = 3/5 = 0.60
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Answer:
D: 0.75
Step-by-step explanation:
<u>Explanation</u>:-
<u><em>Independent events:</em></u>
If the occurrence of the event 'B' is not effected by the occurrence or non- occurrence of the event 'A' then the event 'B' is said to be independent of 'A'
or
<em>The two events are independent if the incidence of one event is not affect the probability of other event.</em>
<em>P(A∩B) = P(A) P(B)</em>
Given data A and B are independent events
Given data
we know that A and B are independent events are
P(A∩B) = P(A) P(B)
Now calculation we get
<u><em>Final answer:</em></u>-