Theorem 10.5: If two parallel lines are cut by a transversal, then the exterior angles on the same side of the transversal are supplementary angles.

6 0

2 years ago

Solve the quadratic by factoring.<br> x^2-5x-31=5

torisob [31]

Answer:

$x = - 4\: or \: x = 9$

Step-by-step explanation:

make one side equal to zero:

${x}^{2} - 5x - 36 = 0$

find two factors that multiply to -36 and add to -5 (-9 & 4)

${x }^{2} - 9x + 4x - 36 = 0$

factorise

$x(x - 9) + 4(x - 9) = 0$

$(x + 4)(x - 9) = 0$

solve for x

$x = - 4 \: or \: x = 9$

5 0

3 years ago

A point R (-2,5) is mapped to point R',as described by a translation of 6 units to the rights and 7 units down.Mark R' on the co

laila [671]

Answer:

(4, -2)

Step-by-step explanation:

Given a point R (-2,5), if the point R' is described by a translation of 6 units to the rights and 7 units down, then the coordinate of R' will be;

6 units to the rights is towards the positive x axis

7 units down is towards the negative y axis

R' = (-2+6, 5-7)

R' = (4, -2)

Hence the coordinate point of R' on the plane is (4, -2)

4 0

2 years ago