Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1
x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
<span>y=-4/x+1 is ambiguous, since it's not immediately clear whether you meant
-4
y = -4/x + 1 or y = ---------
x+1
I'm going to assume that the latter is what you meant.
1. Interchange x and y, obtaining:
-4
x = --------
y+1
2. Solve this for y, obtaining y+1 = -4/x, or xy + x = -4, or
-x - 4
xy = -x-4, or y = ---------
x
-1 -1 4
3. Replace y with f (x): f (x) = -1 - -----
x
This last result has the correct form.</span>
I don't know what c you are talking about because there is no picture
Answer:
Emilio will have both activities again on the same day after 90 days from this Saturday.
Step-by-step explanation:
<em>To solve this question list the multiples of 30 and 9 to find the first common multiple because the two activities will happen again in </em><em>a number divisible by both 30 and 9.</em>
∵ The multiples of 30 are: 30, 60, 90, 120, ............
∵ The multiples of 9 are: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, .....
→ The common multiple is 90
∴ The common multiple of 30 and 9 is 90
→ That means the activities will meet again after 90 days from
this Saturday
Emilio will have both activities again on the same day after 90 days from this Saturday.
Answer:
0 cm³
Step-by-step explanation:
the lost of water =
(5×24)/12 x 1/10 × 18000
= 10/10 × 18000 = 18,000 cm³
so, the remaining water in the tub=
18,000 - 18,000 = 0 cm³
(the tub is empty)
