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Yanka [14]
3 years ago
8

-ayuda ¡¡¡ Se tiene previsto implantar un proyecto de "Caucho sintético" cuya inversión sería de S/ 2 500 000, para un tamaño de

planta de 12 000 toneladas anuales. Luego de estudiar el proyecto, los promotores estiman que es más conveniente un tamaño de 19 200 toneladas por año. ¿A cuánto ascenderá la inversión total, si el exponente del factor de escala es α=0,63? ayuda !!!!!
Mathematics
1 answer:
Bumek [7]3 years ago
4 0

Answer:

En caso de un tamaño de producción de 19,200 toneladas anuales, el costo de inversión total ascenderá a $3,999,936.

Step-by-step explanation:

Dado que la inversión inicial será de $ 2,500,000 para un tamaño de planta de 12,000 toneladas anuales, se estima que cada tonelada requiere una inversión de $208.33 (2,500,000 / 12,000).

Por lo tanto, en caso de una producción anual de 19,200 toneladas, el costo de inversión aumentará según lo establecido en la siguiente multiplicación:

208.33 x 19,200 = X

3,999,936 = X

Por lo tanto, en caso de un tamaño de producción de 19,200 toneladas anuales, el costo de inversión total ascenderá a $3,999,936.

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Serjik [45]
I have
no idea i just need point so i can scan my paper
4 0
2 years ago
Today’s weather report states that it is highly likely to snow today. Which probability best represents the chance of snow today
storchak [24]
It’s c highly likely is more than ,50 and less than 1.00
8 0
2 years ago
From 1960 to 2010, a certain money stock measure was growing at the rate of approximately 43e(1/2)x billion dollars per decade,
natulia [17]

Answer:

1222 billion dollars.

Step-by-step explanation:

To find the total increase from 1960 to 2010, we need to find the growth of each decade and sum them all:

In the period 1960-1970, we have x = 1, and the growth is:

y(1) = 43e(1/2) = 70.895

In the period 1970-1980, we have x = 2, and the growth is:

y(2) = 43e(2/2) = 116.8861

The growth in the following 3 periods are:

y(3) = 43e(3/2) =192.7126

y(4) = 43e(4/2) = 317.7294

y(5) = 43e(5/2) =523.8472

So the total growth in the period 1960 - 2010 is:

Total = y(1) + y(2) + y(3) + y(4) + y(5)

Total = 70.895 + 116.8861+192.726+317.7294+523.8472

Total = 1222.08\ billion\ dollars

Rounding to the nearest billion dollars, we have a total of 1222 billion dollars.

6 0
2 years ago
PLEASE HELP NOWWWW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Ymorist [56]

Answer:

yo is this a quiz is'int it

3 0
3 years ago
10 - 2.5x &gt; 35<br>I need help​
kvasek [131]

Answer:

x<-10

Step-by-step explanation:

10-2.5x>35

2.5x>10-35

2.5x>-25

x>-25/2.5

x>-10

x<-10

8 0
2 years ago
Read 2 more answers
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