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Aleksandr-060686 [28]
3 years ago
6

You are working for a company that creates tubes that measure 10 cm long and have a diameter of 6 cm. The tubes need to be cut j

ust right. The company fired all of its math people so they do not know how to calculate the size of the tube needed. Please calculate the surface area needed for the tube. Use 3.14 for pi. *
Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0

Answer:

A= 2\pi (3cm)^2 +1 2\pi (3cm)(10 cm)= 18 \pi + 60\pi = 78 \pi cm^2

And replacing the value of \pi =3.14 we got:

A = 78*3.14 cm^2= 244.92 cm^2

Step-by-step explanation:

For this case we have the long who represent the height 10 cm and the diameter is 6cm. So then the radius is given by:

r = \frac{D}{2}= \frac{6cm}{2}= 3cm

And the surface area for a cylinder is given by this formula:

A= 2\pi r^2 +2 \pi rh

And replacing the info given we got:

A= 2\pi (3cm)^2 +1 2\pi (3cm)(10 cm)= 18 \pi + 60\pi = 78 \pi cm^2

And replacing the value of \pi =3.14 we got:

A = 78*3.14 cm^2= 244.92 cm^2

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Answer:

62-0.75x8

Step-by-step explanation

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3 years ago
Kenny had 5/7 more trading cards than lee. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee.
svp [43]

Answer:

Step-by-step explanation:

Let X is the number of cards Kenny has

Let Y is the number of cards Lee has

1. Kenny had 5/7 more trading cards than lee, it means

X = Y + 5/7X (1)

2. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee, it means:

X + 50%X = Y +  220 (2)

So, we solve the 2 equations to find out X and Y

\left \{ {{X=Y + 5/7X} \atop {1.5X=Y +220}} \right.

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3 years ago
Please help me find the slope of the line !!
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The slope of the line is 3/2. That would be letter B. You take two points from the graph and subtract them from each other to find the slope. Hope this helps!
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3 years ago
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.
Leni [432]

Answer:

a)

g(2.9) \approx -6.6

g(3.1) \approx -3.4

b)

The values are too small since g'' is positive for both values of x in. I'm speaking of the x values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on that line.

We want to find the equation of the tangent line of the curve g at the point (3,-5) on g.

So we know (x_1,y_1)=(3,-5).

To find m, we must calculate the derivative of g at x=3:

m=g'(3)=(3)^2+7=9+7=16.

So the equation of the tangent line to curve g at (3,-5) is:

y-(-5)=16(x-3).

I'm going to solve this for y.

y-(-5)=16(x-3)

y+5=16(x-3)

Subtract 5 on both sides:

y=16(x-3)-5

What this means is for values x near x=3 is that:

g(x) \approx 16(x-3)-5.

Let's evaluate this approximation function for g(2.9).

g(2.9) \approx 16(2.9-3)-5

g(2.9) \approx 16(-.1)-5

g(2.9) \approx -1.6-5

g(2.9) \approx -6.6

Let's evaluate this approximation function for g(3.1).

g(3.1) \approx 16(3.1-3)-5

g(3.1) \approx 16(.1)-5

g(3.1) \approx 1.6-5

g(3.1) \approx -3.4

b) To determine if these are over approximations or under approximations I will require the second derivative.

If g'' is positive, then it leads to underestimation (since the curve is concave up at that number).

If g'' is negative, then it leads to overestimation (since the curve is concave down at that number).

g'(x)=x^2+7

g''(x)=2x+0

g''(x)=2x

2x is positive for x>0.

2x is negative for x.

That is, g''(2.9)>0 \text{ and } g''(3.1)>0.

So 2x is positive for both values of x which means that the values we found in part (a) are underestimations.

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4 years ago
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