The residents of a certain dormitory have collected the following data: People who live in the dorm can be classified as either
involved in a relationship or uninvolved. Among involved people, 15 percent experience a breakup of their relationship every month. Among uninvolved people, 30 percent enter into a relationship every month. What is the steady-state percentage of residents who are uninvolved?
To obtain the steady state percentage of residents who are uninvolved, we could relate the scenario to the natural unemployment rate relation : seperation rate ÷ (seperation rate * finding rate)
Hence, we could use the Relation as this ;
Breakup percentage ÷ (Breakup percentage + new relationship rate)
The equation here is 1 1/4 X 6 1X6= 6 and 1/4 X6 = 6/4 You can add these to and the answer is 6 6/4 which can then be simplified to 7 1/2 hours in 6 days
