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anastassius [24]
3 years ago
15

What can you use with your keywords to narrow your search if you complete an internet search using a search engine and do not ge

t the results you want?
Computers and Technology
2 answers:
Salsk061 [2.6K]3 years ago
8 0
Boolean operators such as +, -, etc.
Oliga [24]3 years ago
7 0
You would use the Boolean Operators- Hope this helps :)
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The code the application software needs in order to interact with the CPU

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In the story, what are the song pauses a metaphor for?
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D. The need to slow down more often in life.

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Servers that exist within a data center that is publicly accessible on the internet are referred to as on-premises servers.
adoni [48]

Servers that exist within a data center that is publicly accessible on the internet are referred to as on-premises servers: b. false.

<h3>What is a server?</h3>

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7 0
1 year ago
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
2 years ago
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