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Hunter-Best [27]
3 years ago
5

Peter is a 40-year-old average income earner. He is ready to start planning for retirement, and plans to make the maximum possib

le contribution to an IRA, which is currently $5,000 per year. Because he still has 25-30 years until retirement, Peter wants to invest most of the contributions to the IRA in higher risk securities. His hope is that, when the economy is strong, he'll make some large gains on the account. At this point, which type of IRA would be best for Peter, a Traditional or Roth IRA?
I think the answer would be a Roth IRA. I'm not all that sure though.
Mathematics
1 answer:
Bad White [126]3 years ago
6 0
Roth IRA doesn't get you a tax deduction for the contributions, but the earnings grow tax free and you don't pay tax on the withdrawals after retirement. A traditional IRA gives you a tax deduction for the contributions at the time you make them, and the earnings grow tax free, but when you withdraw the money after retirement, you are taxed on it. The idea is that you are hopefully in a lower tax bracket at that point. So its only natural that Roth IRA is the best.
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If you substitute the variable with the lengths of the legs in ascending order, you will get 3^2+4^2=5^2. Simplifying the equation, you will get 9+16=25, or 25=25. Thus, proving the equation.

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The first task of the Segment Two Honors Project is to select the Power Pill study participants’ groups and research board offic
Tatiana [17]

Answer:

Part 1: There are 4.7*10^21 ways to select 40 volunteers in subgroups of 10

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Step-by-step explanation:

Part 1:

The number of ways in which we can organized n elements into k groups with size n1, n2,...nk is calculate as:

\frac{ n!}{ n1!*n2!*...*nk! }

So, in this case we can form 4 subgroups with 10 participants each one, replacing the values of:

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We get:

\frac{ 40!}{10!*10!*10!*10!} = 4.7*10^{21}

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The number of ways in which we can choose k element for a group of n elements and the order in which they are chose matters is calculate with permutation as:

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We get:

\frac{ 15!}{ (15-4)! } = 32760

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