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tankabanditka [31]
4 years ago
7

The dog has gone 5/8 of the way across the yard. How much farther does it have to go to reach the gate?

Mathematics
1 answer:
tigry1 [53]4 years ago
7 0
<span>Well if one assumes that the dog is starting at one side opposite the gate and is heading directly for it, then it has 3/8 of the yard to go. However since one cannot know where the dog has started his movement toward the gate then the answer would not be solvable without more information.</span>
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Ms santos seashells into 4 row she puts 6 seashells in each row how many seachells are there altogether
kati45 [8]
4 rows and 6 seashells in each row. 
Row 1: 0 0 0 0 0 0
Row 2: 0 0 0 0 0 0
Row 3: 0 0 0 0 0 0
Row 4: 0 0 0 0 0 0

You add all of them together 6+6+6+6=24 
Or you could do 6x4 and your answer would be 24
So the answer to the question is 24 seashells. 
3 0
3 years ago
Estimate how much MORE water it would take to completely FILL the vase to the top?
MariettaO [177]

Answer:

81πinc^3

Step-by-step explanation:

Volume of glass = π(3)^2(12) = 108πin^3

Volume of water in glass = π(3)^2(3) = 27πin^3

Volume needed to fill completely = 108π - 27π = 81π^3

Topic: Mensuration

If you like to venture further, please give my Instagram page a follow (learntionary). I'll be constantly posting math tips and notes! Thanks!

6 0
3 years ago
What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2?
xenn [34]
For the answer to the question above asking the explicit equation and domain for an arithmetic sequence with the first term of 5 and the second term of 2? I think the answer for this is <span>5-2(n-1); all integers where n≥0. I hope this helps.</span>

7 0
3 years ago
Read 2 more answers
2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).
castortr0y [4]

Let

F--------> represent the force

m--------> represent the mass

a-------> represent the acceleration

we know that

The formula that relates three quantities: Force (F), mass (m), and acceleration (a) is equal to

F=ma

<u>Part a)</u> Solve this equation for a

F=ma

Divide both sides by the mass

a=\frac{F}{m}

therefore

<u>the answer part a) is equal to</u>

a=\frac{F}{m}

<u>Part b) </u>Let the force be 25 units and the mass be m = 10 units. What is the acceleration, a?

we know that

the formula of acceleration is equal to

a=\frac{F}{m}

in this problem

we have

F=25\\m=10

Substitute the values n the formula

a=\frac{25}{10}

a=2.5

therefore

<u>the answer part b( is equal to</u>

a=2.5

<u>Part c)</u> Let the force be F = 25 units and the acceleration be a = 5 units. What is the mass, m?

we know that

F=ma

Solve for m

Divide both sides by the acceleration

m=\frac{F}{a}

in this problem

we have

F=25\\a=5

Substitute the values n the formula

m=\frac{25}{5}

m=5

therefore

<u>the answer Part c) is </u>

m=5

5 0
3 years ago
Read 2 more answers
Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti
almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

d=v.t

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

d=(x+y).t_1

Where t1=2.5 hours. Substituting values:

20=(x+y)*2.5

Rearranging, we find the downstream equation:

2.5x+2.5y=20\qquad[1]

The speed when rowing upstream is x-y, and the distance traveled is

d=(x-y).t_2

Where t2=5 hours. Substituting values:

20=(x-y)*5

Rearranging, we find the upstream equation:

5x-5y=20\qquad[2]

Multiplying [1] by 2:

5x+5y=40

Adding this equation to [2]:

10x=60

Solving:

x=60/10=6

Dividing [2] by 5:

x-y=4

Solving for y

y=x-4=6-4=2

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0
4 years ago
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