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3 years ago

PLZ HELP ASAP!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

nika2105 [10]3 years ago

4 0

2. A
4. D
I don't know the rest but good luck.

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Quadrilateral ABCD is similar to quadrilateral EFGH. Find the measure of side EF

garri49 [273]

Answer:

EF = 6.6

Step-by-step explanation:

Since ABCD is similar to EFGH, then EH is similar to AD. So, we can solve by first dividing 12 by 2 (EH by AD). The quotient of this is 6. This tells us that quadrilateral EFGH is 6 times larger than quadrilateral ABCD, since they are similar. So, with this and the measurement of AB (which is similar to EF), we can now solve for EF. We simply multiply 1.1 (the measurement of AB) by 6 (how many times larger EFGH is compared to ABCD). The product of this is 6.6, our final answer.

3 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST AND GIVE 5.0 STAR RATING

Sloan [31]

The answer is 5.8 because you find the difference on the x axis and you can’t have a negative distance so yea 5.8

3 0

2 years ago

Read 2 more answers

Aya = a1 + (n - 1)d

Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

Step-by-step explanation:

Given

a₁ = -33

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = -33 and d = 4 in the nth term of the sequence

$a_n=-33+\left(n-1\right)4$

$\:a_n=-33+4n-4$

$a_n=4n-37$

Thus, the nth term of the sequence is:

$a_n=4n-37$

now substituting n = 26 in the nth term to determine the 26th term of the sequence

$a_n=4n-37$

$a_{26}=4\left(26\right)-37$

$a_{26}=104-37$

$a_{26}=67$

Therefore, the 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

7 0

2 years ago

a dragonfly can beat its wings 30 times per seconed.write an equation in slope intercept from that shows the relationship betwee

Andreas93 [3]

Answer:

$s=30f$

Step-by-step explanation:

S = second; F = flying time.

Since it can flap its wings 30 times, each second, we have already found our answer. The relationship between flying time (Wing flaps) and seconds is 30. In other words, it beats it's wings 30 times each second. Which is what the question asks.

Now we just have to write the equation:

$s=30f$

This is because the seconds are <u>dependent</u> on the flap of wings, so s would be the y value.

Hope it Helps!

4 0

3 years ago

Mr. Crawford’s 4th-Period math class I ready question

drek231 [11]

Answer:

yes

Step-by-step explanation:

yes

6 0

3 years ago