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3 years ago

F (x)=10-4x find the inverse function

Mathematics

1 answer:

Dafna1 [17]3 years ago

4 0

Y=-1/4x+10/4

change the x and y variables and then solve for y again. that's your answer

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Solve the equation, and check the solutions 2(√x+3)=6.

zhannawk [14.2K]

Answer:

x = 0

Step-by-step explanation:

$2(\sqrt{x}+3)=6$

Expanding the left hand side we get

$\Rightarrow 2\sqrt{x}+6=6$

Taking 6 from left hand side to right hand side

$\Rightarrow 2\sqrt{x}=6-6\\\Rightarrow 2\sqrt{x}=0$

Dividing both sides by 2

$\Rightarrow \sqrt{x}=\frac{0}{2}\\\Rightarrow \sqrt{x}=0\\\Rightarrow x=0$

So, x = 0

4 0

3 years ago

Use unit rate to find the unknown value 16/32 equals blank over 14

grigory [225]

Answer:

x = 7

Step-by-step explanation:

simplify 16/32

16/32 divided by 8/8=2/4

2/4 divided by 2=1/2

1/2 = x/14

to get to 14 from 2 you need to multiply by 7

1/2 times 2/2 = 7/14

so x = 7

5 0

3 years ago

HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION RQ!!!!!!!!

Ilya [14]

Answer:

the answer is A i hope this helps you! may i have brainly?:)

Step-by-step explanation:

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3 years ago

If Kansas City is 108 miles away how many gallons of gas I needed to get there and then home

fenix001 [56]

Answer:

Well here's the issue...

Step-by-step explanation:

Since we have no idea what car you'll be using for the experiment, I can't tell you how many times you will have to fill er' up either. let's say you have a fuel efficient car like 27 mpg. that's highway and city combined. (34/25) And the trip is 216 miles round trip. And let's say you used 0 gallons while you were there. You would need to fill up exactly 8 times to get there and back. That's going off of 27 miles per gallon.

Hope this helps!!

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3 years ago

Determine whether the statement is true or false, and explain why.

Zielflug [23.3K]

Answer:

False

Step-by-step explanation:

In this case, i woudnt reccomend to use integration by parts, becuase you are not simplifying the expression by doing an integration and a derivation. It is not easy to integrate 1/x³+1, and if you derivate it, then a natural logarithm would appear, and the integral wont be easier after this parts step.

It is a better idea to use integration by substitution. Note that if you replace x³+1 by a variable y, we have that dy = 3x² dx. We can easily make a 3xdx appear in the integral by multiplying and dividing by 3, solving the integral easily:

$\int\limits_0^1 x^2/x^3+1 \, dx = 1/3 * \int\limits_1^2 du/u = (ln(2) - ln(1) )/3$

(Note that, if x ranges from 0 to 1, then u = x³+1 ranges from 0³+1 = 1 to 1³+1 = 2)

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3 years ago