To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
Answer:
you will pay 274.75 at month 5 for both companies
company A: 42.95x+60.00
company B. 49.95x+25.00
Step-by-step explanation:
Answer:
x = -4, y = -2
Step-by-step explanation:
substitute for y
2x - 5(x + 2) = 2
distribute -5
2x -5x - 10 = 2
solve
-3x - 10 = 2
add 10 on both sides
-3x = 12
divide by -3
x = -4
now substitute for x in the equation y = x + 2
y = -4 + 2
y = -2
