Answer:
P(X=2)=0.04129
Step-by-step explanation:
-This is a binomial probability problem whose function is expressed as;

-Given that p=0.6, n=8 , the probability that among the students in the sample exactly two are female is calculated as:

Hence, the probability of exactly two females is 0.04129
4 gallons
If half covers an eighth, then you need half a total if 8 times. So multiply half by 8 and you get 4.
If this helped please mark branliest
Answer:

Step-by-step explanation:

Correct me if im wrong but the answer is (B) hope this helps!