To solve this multiply through by the LCM of 4 and 6, which is 12:-
12 * x/4 - 12 * x/6 = 1*12
3x - 2x = 12
x = 12 answer
Answer:
a). Mileage for carA= 
, and mileage for carB=
b).total mileage for both is similar to average of them= 
=![\frac{5x+4}{2x(x+1)}[tex]mil/gal](https://tex.z-dn.net/?f=%5Cfrac%7B5x%2B4%7D%7B2x%28x%2B1%29%7D%5Btex%5Dmil%2Fgal)
Step-by-step explanation:
It is given that the distance traveled by car 
And distance traveled by car 
We know the mileage is mile/gallon,
a).So mileage of car 
Similarly , the mileage for car 
b).total mileage for both is similar to average of them=
Now divide by 2 for total(average) mileage.
.
Thus those are the answers.
Jill put 10.3 gallons of gas into her car. She drove for 473.8 miles.
So we have to find how many miles per gallon she drove.
473.8 into 10.3 = 46
To make sure= 10.3 x 46 = 473.8
So Jill drove 46 miles per gallon.
Answer:
D.
40 x 6.4 = 256
256/128=2 so 2 gallons.
Step-by-step explanation:
I will solve your system by substitution.<span><span>x=<span>−2</span></span>;<span>y=<span><span><span>23</span>x</span>+3</span></span></span>Step: Solve<span>x=<span>−2</span></span>for x:Step: Substitute<span>−2</span>forxin<span><span>y=<span><span><span>23</span>x</span>+3</span></span>:</span><span>y=<span><span><span>23</span>x</span>+3</span></span><span>y=<span><span><span>23</span><span>(<span>−2</span>)</span></span>+3</span></span><span>y=<span>53</span></span>(Simplify both sides of the equation)
Answer:<span><span>x=<span>−<span><span>2<span> and </span></span>y</span></span></span>=<span>5/3
<span>
so the answer is B (the second choice)
(Hope it helped ^_^)
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