Quadratic: ax^2+bx+c
a=1
roots=-4,2
=(x-(-4))(x-2)
=(x+4)(x-2)
=x^2+4x-2x-8
=x^2+2x-8
Answer:
digits are: 0, 4, 8. The required number is: 480.
Step-by-step explanation:
→ Let ones digits is 'x', then according to the condition the hundreds digit is 'x+4', and the tens digit is '2(x+4)'.
→ According to the condition the sum of the digits is: x+(x+4)+2(x+4)=12.
→ After evaluation this equation, x=0 - this is ones digit;
→ x+4=0+4=4 - this is hundreds digit;
→ 2(x+4)=2(0+4)=8 - this is ten digit.
Answer:
above is the answer to the question
The answer is 3. if 81 balls are divided equally into 3 groups there would be 27 balls in each group.