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ExtremeBDS [4]
2 years ago
7

What is the product of x2 - 2x +3 and x+1?

Mathematics
1 answer:
Leno4ka [110]2 years ago
5 0
The answer would be 3, 2-2+3, I’m pretty sure.
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Find X : log2+ logx=1
Dominik [7]
log2+logx=1;\ D:x\in\mathbb{R^+}\\\\log(2\ \cdot\ x)=log10\iff2x=10\ \ \ /:2\\\\x=5\in D\\\\Solution:x=5.
8 0
3 years ago
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3) Which expression is equivalent to: 6(7-2) *<br> O 67-62<br> O42-12<br> O 7-2<br> O 13 - 8
Vlad1618 [11]

Answer:

42-12

Step-by-step explanation:

Here you go mate

Step 1

6(7-2)  Equation

Step 2

6(7-2)  simplify

6x5

answer

42-12=30  check

4 0
2 years ago
Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
2 years ago
​PLEASE HELP! I will give you the brainiest and A LOT of points!
Alja [10]

Answer:The solution is in the attached file

Step-by-step explanation:

7 0
2 years ago
Plot the coordinates
forsale [732]

Answer:

Quadrilateral

Explanation:

there are only for points,

triangle= three points

hexagon= 6 points

pentagon= 5 points

4 0
3 years ago
Read 2 more answers
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