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zhenek [66]
3 years ago
10

What equation is the inverse of y=2x^2-8?

Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0

Step-by-step explanation:

To get the inverse, swap the x- and y-variables, then solve for y. We should have the equation: x = 2y^2 - 8

Solving for y:    

y = 2x^{2} - 8    because  y + 8 = 2x^{2} or  x =\sqrt\frac{y +  8}{2}

So on interchanging the variable, we get the equation:

x = 2y^2 - 8

x + 8 = 2y^2

y = \sqrt\frac{x + 8}{2}

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Answer:

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Step-by-step explanation:

According to the question,

x∝y^3          .......(1)

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From equation 1,2 let constant of proportionality be k1,k2 respectively.

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From the above equations putting 4 into 3,

x=k1((k2\sqrt{z})^3) =k1.k2^3.(\sqrt{z})^3

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⇒\sqrt{z}=3(2)=6

z=36

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