You need to make a series of equations from what you are given first. I am going to use the first letter of each of the names to represent the length of that persons wire.
1/2s=2/5d
3c=s
s+d+c=6 ft
Okay. Now you can combine the first two equations knowing what s equals:
1/2(3c)=2/5d
d=15c/4
Now you have d=15c/4 and s=3c, so you can replace d and s in the third equation.
3c+15c/4+c=6
Then solve for c and plug it into the equation 3c=s to find the length of sarah's wire.
Since sides kl and kj are congruent that means that angles klj and kjl are congruent. if angle klj is 58 then that means kjl is also 58. so you take the total number of degrees in a triangle (180) and subtract 58 and 58 (116) which leaves you with 64 ( the degree measure of lkj)
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
3,000+4,000+1
Three hundred four thousand, one
Wen you deduct an amount from something