Answer: the height in inches, of the pile after 3 weeks is 34 11/12 inches
Step-by-step explanation:
Each consecutive week for the next 5 weeks the height of pile increase by 8 7/12 inches. Converting 8 7/12 inches to improper fraction, it becomes 103/12 inches. The height is increasing in an arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = 17 3/4= 71/4 inches
d = 103/12 inches
n = 3 weeks
the height in inches, of the pile after 3 weeks, T3. Therefore,
T3 = 71/4 + (3 - 1)103/12
T3 = 71/4 + 2 × 103/12 = 71/4 + 103/6
T3 = 419/12 inches = 34 11/12 inches
Hello!
The answer is 20/60 simplest form is 1/3
To get 20/60 you must multiply the Numerator by Numerator (4*5) and Denominator by Denominator (5*12). Your answer will be 20/60.
To get 1/3 you must simplify a number that can go into 20 and 60 (which is 10). Divide 20/10 and 60/10 and get 2/6. Simplify 2/6 by 2 and get 1/3.
Since the average height is 60 inches and its deviation is 2 inches, one deviation to the right (or higher) is 62 inches (60 + 2). Two deviations is 64 inches, three deviations is 66 inches, and four deviations is 68 inches.
Since the average weight is 100 pounds and its deviation is 5 inches, we repeat the process from finding heights to get to 115 pounds. That takes three deviations.
The MORE deviations away, the more unusual it is. So the height (4 deviations) is more unusual than the weight (3 deviations).
1/3(x)=22-x
x/3=22-x
(x/3=22-x)3
3x=66-3x
6x=66
x=11
