<h2>
Hello!</h2>
The answer is:
The ball will hit the ground after
<h2>
Why?</h2>
Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula. We must take into consideration that we are talking about time, it means that we should only consider positive values.
So,
We are given the function:
Where,
Then, substituting it into the quadratic equation, we have:
Since negative time does not exists, the ball will hit the ground after:
Have a nice day!
This is harder than it looks I cant figure it out
9514 1404 393
Answer:
(√17 -4√595)/102
Step-by-step explanation:
To use the sine of the angle sum formula, we need to know the sine and cosine of each of the angles.
sin(sin^-1(1/6)) = 1/6 . . . . a first-quadrant angle
cos(sin^-1(1/6)) = √(1 -(1/6)²) = √(35/36) = (√35)/6
sin(tan^-1(-4)) = -4/√(1+(-4)²) = -4/√17 . . . . a 4th-quadrant angle
cos(tan^-1(-4)) = √(1 -(-4/√17)²) = 1/√17
The sum of angles formula is ...
sin(α+β) = sin(α)cos(β) +cos(α)sin(β)
So, our sine is ...
Answer:
8 intersections
Step-by-step explanation:
Miss Stevens drove through a total of 36 intersections on her way home from work last week.
At four of every 16 intersections Miss Stevens had to stop for a red light before she could drive through .
This is calculated as:
36 intersections ÷ 16 intersections
= 2 4/16
= 2 1/4
At four of every 16 intersections Miss Stevens had to stop for a red light before she could drive through .
4 of every 16 intersections = stop for a red light
Hence:
16/4 = 4 intersections
Hence: 4 intersections = 1 stop for a read
The number of intersections that Miss Stevens had to stop for a red light is:
2 × 4 intersections = 8 intersections
Answer:
C
Step-by-step explanation:
It looks impossible to tell if you don't know one simple fact. You have to know that the Plane that contains WTSR and V is opaque which means you can't see through it. So the line that goes through it (containing WQ) is partially not seen.
It is represented by a dashed line that shows the line is there, but it is invisible.
So Q is on the plane, but W is not. W is the answer.