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Helen [10]
3 years ago
9

Based on these equations, which one represents the greatest rate?

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0

For the 1st one its...

y = 7x + 5.

For the 2nd one its...

Choice C: 32

For the 3rd its...

Choice A: 3/4

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A triangle has a perimeter of 16x + 4. If Side 1 is 3x + 2, Side 2 is 8x + 7, what is the measure of Side 3?
scoundrel [369]

Answer:

5x - 5

Step-by-step explanation:

To find the missing side, add the two sides together and subtract them from the perimeter.

side 1 + side 2

3x + 2 + 8x + 7

combine like terms

11x + 9

Subtract from the perimeter

16x + 4 - (11x + 9)

rewrite as an addition problem, so you need to change the signs inside the parentheses.

16x + 4 + (-11x -9)

Now combine like terms

5x - 5

8 0
3 years ago
Find the measure of one interior angle in each regular polygon.
Luda [366]

Answer:

108°

Step-by-step explanation:

Polygon has <em>n</em> sides.

Each interior angle = 180° - (360/n)°

<em>n</em> = 5 ⇒ interior angle = 180° - (360/5)° = 108°

7 0
3 years ago
There are no results for The impedance Z in an AC (alternating current) circuit is a measure of how much the circuit impedes (hi
Semmy [17]

Answer:

Step-by-step explanation:

If the impedance is related to the voltage and the current by the formula V = IZ where;

V is the voltage

I is the current

Z is the impedance

Given

I = 0.4+3i

V = 0.3-2i

Voltage V = (0.4+3i)(0.3-2i)

V = 0.4(0.3)-0.8i+0.9i-6i²

V = 0.12+0.1i -6i²

Since i² = -1

V = 0.12+0.1i-6(-1)

V = 0.12+0.1i+6

V = 6.12+0.1i.

Hence the impedance is 6.12+0.1i

7 0
3 years ago
Evaluate −3x+y2÷(−1) when x=8 and y=5.
vekshin1

Answer:

-34

brainlist please?

4 0
3 years ago
Help plsss
LenKa [72]
<h3></h3><h2>⭐ Development:</h2><h3></h3>

  • Having the expression, let's modify it so it becomes a 2nd degree equation:

\large {\text {$ \sf \cfrac{1}{2x^2} -2 = 0 $}}

  • Now, we will multiply per 2x² both sides of equation...

\large {\text {$ \sf \cfrac{1}{2x^2}\cdot \:2x^2-2\cdot \:2x^2=0\cdot \:2x^2 $}

                 \searrow

                     \large {\text {$ \sf 1-4x^2=0$}}

  • We have to write in standard form...

\large {\text {$ \sf -4x^2+1 = 0 $}}

<u>                                                                                                      </u>

<u />

\large {\text{$\sf x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2a} \quad\rightarrow\quad x=\cfrac{-0\pm\sqrt{0^2-4\cdot (-4) \cdot1} }{2\cdot (-4) } \:\rightarrow\:\: x=\cfrac{-0^2 \pm4}{2 \cdot(-4)}    $}}  

                                                                                                                         

                                                             \huge {\text {$ \sf \downarrow$}}

                                                                                                         

           \large {\text {$\sf {\bf x_1} = \cfrac{-0+4}{2\left(-4\right)}= \cfrac{-1}{2}  $}}                        \large {\text {$\sf {\bf x_2 }=\cfrac{-0-4}{2\left(-4\right)} = \cfrac{1}{2}  $}}

  • At this point, we're going to add the values ​​of x₁ and x₂:

\large {\boxed {\boxed { \bf x_1 + x_2=  -\cfrac{1}{2}+ \cfrac{1}{2} = 0}  }}

                                           \huge {\text {$ \it  Alternative \: A $}}

8 0
3 years ago
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