Answer:
D.all lipids contain fatty acids.
Explanation:
A.Lipids are fats, like oil, that are insoluble in water. ... The most abundant class of lipid molecule found in cell membranes is the phospholipid. The phospholipid molecule's polar head group contains a phosphate group. It also sports two nonpolar fatty acid chain groups as its tail.
B.The simplest definition is a lipid as any molecule that is insoluble in water and soluble in organic solvents. Most lipids are soluble to some extent in organic solvents such as hexane, ether, chloroform or benzene. They constitute a complex collection organic compounds that include fatty acids, (A,D, E and K).
C.There are two major types of lipids- simple lipids and complex lipids. Simple lipids are esters of fatty acids with various alcohols. For eg., fats and waxes.
D.Not all lipids have fatty acids. The operational definition of a lipid is a biomolecule is that is sufficiently hydrophobic to be more soluble in an organic solvent than in water. The common theme to their structures is a high percentage of hydrocarbon character.
E.Most lipid hormones are steroid hormones, which are usually ketones or alcohols and are insoluble in water. Steroid hormones (ending in '-ol' or '-one') include estradiol, testosterone, aldosterone, and cortisol. ... Amino acid-derived hormones and protein hormones are water-soluble and insoluble in lipids.
Answer: No I read it on briticanna.com
Explanation:
Answer:
The order must be K2→K1, since the permanently active K1 allele (K1a) is able to propagate the signal onward even when its upstream activator K2 is inactive (K2i). The reverse order would have resulted in a failure to signal (K1a→K2i), since the permanently active K1a kinase would be attempting to activate a dead K2i kinase.
Explanation:
- You characterize a double mutant cell that contains K2 with type I mutation and K1 with type II
mutation.
- You observe that the response is seen even when no extracellular signal is provided.
- In the normal pathway, i f K1 activat es K2, we expect t his combinat ion of two m utants to show no response with or without ext racell ular signal. This is because no matt er how active K1 i s, it would be unable to act ivate a mutant K2 that i s an activit y defi cient. If we reverse the order, K2 activating K1, the above observati on is valid. Therefore, in the normal signaling pathway, K2 activates K1.
Answer:
Explanation:transcription/RNA processing:
a) snRNA
c) mRNA
e) pre-mRNA
2. translation
b) tRNA
f) rRNA
3. not used in protein synthesis
d) RNA primers
